9x^2-61x+80=0

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Solution for 9x^2-61x+80=0 equation:



9x^2-61x+80=0
a = 9; b = -61; c = +80;
Δ = b2-4ac
Δ = -612-4·9·80
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-29}{2*9}=\frac{32}{18} =1+7/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+29}{2*9}=\frac{90}{18} =5 $

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